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Aldehyde
& Ketone
-CHO AND - CO -
Definition
Of Aldehyde
“Organic compounds that contain monovalent functional group –CHO are known as aldehydes.”
General
Formula Of Aldehyde
They are denoted by RCHO, where R may be any alkyl group. The general formula for aldehyde is:
CnH2n – CHO
Where n may be any natural number.
Structure
Of Aldehyde
The structural formula of aldehyde shows that it contains a carbonyl group.
Examples
Of Aldehyde
· CH3CHO (Acetaldehyde)
· HCHO (Formaldehyde)
Definition
Of Ketone
“Organic compounds that contain divalent functional group – CO – are called Ketones.”
General
Formula Of Ketone
They are denoted by R may be any alkyl group. The general formula for Ketone is:
CnH2n+1 – CO – CnH2n+1
Where n may be any natural number.
Structure
of Ketone
The structural formula of ketone shows that it contains a carbonyl group.
Example
Of Ketone
· CH3COCH3 (Acetone)
Preparation
of Aldehyde & Ketone
Aldehyde and Ketone can be prepared by the following methods:
1. From Dehydrogenation of Alcohol
Removal of hydrogen from a compound is called dehydrogenation. In presence of catalyst, Cu – Ni couple when alcohol is heated at 180°C then dehydrohalogenation takes place. As a result, aldehyde and ketone are formed.
H-CH2OH ® H-CH=O + H2
Form Aldehyde
CH3-CH2OH ® H-CH=O + H2
Acetaldehyde
(CH3)2-CH-OH ® (CH3)2-C=O + H2
Acetone
2. From Oxidation of Alcohol
In presence of oxidizing agents, K2Cr2O7 or concentrated H2SO4, alcohols are oxidized to form aldehyde or ketone.
H-CH2OH +
[O] ® H-CH=O + H2O
Form Aldehyde
CH3-CH2OH + [O] ® H-CH=O + H2O
Acetaldehyde
(CH3)2-CH-OH + [O] ® (CH3)2-C=O + H2O
Acetone
3. From Dry Distillation
By the dry distillation of calsium formate (Calsium salt of formic acid), form aldehyde is obtained.
Ca(COOH)2 ® HCHO + CaCO3
By the dry distillation of calsium salt of formic acid and calsium salt of carboxylic acid, aldehydes are obtained.
Ca(CH3OOH)2 + Ca(COOH)2 ® CH3CHO + CaCO3
By the dry distillation of calsium salt of carboxylic acid, Ketone is formed.
Ca(CH3OOH)2 ® CH3CHO + CaCO3
1. From Ethyne
This method is used for the preparation of acetaldehyde. In presence of catalyst H2SO4 and HgSO4 when ethyne reacts with water than unstable, intermediate vinyle alcohol is formed which on rearrangement of atoms convert into acetaldehyde.
H-CºC-H + H20 ® H2C-HCOH ® H3C-COH
Preparation
of Acetone By Pyrolysis Of Acetic Acid
In presence of catalyst MnO2, when the acetic acid is heated at about 500°C then acetone is formed.
CH3COOH ® CH3-CHO + CO2 + H20
Chemical
Properties Of Aldehyde & Ketone
Some important chemical reactions of aldehyde and ketone are given below:
1. Addition Reaction due to Carbonyl Group
The carbonyl group of aldehyde and ketone is polarized by due to the high electronegativity of oxygen atom. The shared pair of electron (p electrons) is shifted towards oxygen atom as a result the carbonyl carbon becomes partial positively charged and oxygen becomes partial negatively charged. Due to the presence of double bond, carbonyl group shows addition reaction. When aldehyde and ketone reacts with electorphillic reagent then addition reaction takes place as a result product is formed.
=C+=O- + A+B- ® =CB-OA
Carbonyl Electrophilic Addition
Group Reagent Product
Some important addition reactions of aldehyde and ketone are given below:
a)Reaction with Hydrogen Cyanide
When aldehyde or ketone reacts with hydrogen cyanide then cynohydrin is formed.
H2C=O + HCN ® H2C-CN-OH
Form
Aldehyde CynoHydrin
CH3HC=O + HCN ® CH3HC-CN-OH
Acetaldehyde
(CH3)2C=O + HCN ® (CH3)2C-CN-OH
Acetone
b)Reaction with Ammonia
When aldehyde and ketone reacts with ammonia then hydroxyl amine is formed.
H2C=O + HNH2 ® H2C- NH2-OH
Form
Aldehyde Hydroxile
Amine
CH3HC=O + HNH2 ® CH3HC- NH2-OH
Acetaldehyde
(CH3)2C=O + HNH2 ® (CH3)2C- NH2-OH
Acetone
c)Reaction with Alcohol
When aldehyde or ketone reacts with alcohol (ethyl alcohol) the hemi acetal is formed.
H2C=O + C2H5OH ® H2C- C2H5O-OH
Form
Aldehyde
CH3HC=O + C2H5OH ® CH3HC- C2H5O-OH
Acetaldehyde
(CH3)2C=O + C2H5OH ® (CH3)2C- C2H5O-OH
Acetone
2. Substitution Reaction due to Carbonyl Group
When aldehyde and ketone reacts with the compound containing H2, then oxygen of carbonyl group combines with Hydrogen of the attacking molecule to form water and substituted product.
Some important substitution reactions of aldehyde and ketone are given below:
a)Reaction with Hydroxyl Amine
When aldehyde and ketone reacts with hydroxyl amine then oxine is formed.
H2C=O + H2NOH ® H2C=NOH + H2O
Form
Aldehyde
CH3HC=O + H2NOH ® CH3HC=NOH + H2O
Acetaldehyde
(CH3)2C=O + H2NOH ® (CH3)2C=NOH + H2O
Acetone
b)Reaction with Hydrazene (NH2 – NH2)
When aldehyde and ketone reacts with Hydrazene then hydrazone is formed.
H2C=O + H2N-NH2 ® H2C=N-NH2 + H2O
Form
Aldehyde
CH3HC=O + H2N-NH2 ® CH3HC=N-NH2 + H2O
Acetaldehyde
(CH3)2C=O + H2N-NH2 ® (CH3)2C=N-NH2 + H2O
Acetone
c)Reaction with Phenyl Hydrazene
When aldehyde and ketone reacts with Phenyl hydrazene then Phenyl Hydrazene is formed.
H2C=O + H2N-NHC6H5 ® H2C= N-NHC6H5 + H2O
Form
Aldehyde
CH3HC=O + H2N-NHC6H5 ® CH3HC= N-NHC6H5 + H2O
Acetaldehyde
(CH3)2C=O + H2N-NHC6H5 ® (CH3)2C= N-NHC6H5 + H2O
Acetone
3. Oxidation of Aldehyde & Ketone
In presence of oxidizing agent such as a mixture of K2Cr2O7 and H2SO4, when aldehyde is oxidized then acids are formed.
H2C=O + [O] ® HCOOH
Form
Aldehyde
CH3HC=O + [O] ® CH3COOH
Acetaldehyde
(CH3)2C=O + [O] ® CH3COOH + CO2 + H20
Acetone
4. Reaction with Fehling’s Reagent
The alkaline solution of copper hydroxide and sodium hydroxide is called Fehling’s solution. When aldehydes are warmed with Fehling’s reagent then red precipitates of cuprous oxide are formed. In this reaction Cu+2 is reduced to Cu+1. Due to the presence of terminal hydrogen i.e. the hydrogen bonded with carbonyl carbon atom. Aldehyde act as reducing agent.
CH3HC=O + Cu(OH)2 + NaOH ® CH3COONa + Cu2O + 3H2O
Ketones do not react with Fehling’s reagent because in ketone hydrogen is not directly bonded with carbonyl carbon atom. Therefore, this test is use to distinguish between aldehyde and ketone in laboratory.
5. Reaction with Tollen’s Reagent
The ammonical silver nitrate solution is called Tollen’s reagent. When aldehyde reacts with Tollen’s reagent then metallic silver is produced which is deposited on a fine smooth surface forming silver mirror. In aldehyde the carbonyl carbon is bonded with hydrogen atom, due to presence of terminal hydrogen aldehyde acts as reducing agent and it reduces Ag+1 to Ag0 which is deposited on smooth surface forming silver mirror.
CH3HC=O + [Ag(NH3)2]OH